Well, solvents are chosen for purpose. 1.When the sodium iodide solution is added to the unknown, a precipitate of sodium iodide might occur leading to a false positive test. 2) When treated with sodium iodide in acetone, benzyl chloride reacts much faster than 1-chlorobutane, even though both compounds are primary alkyl chlorides. the carbon halogen bond is weakened because a molecule of insoluble silver halide is … 1)In the test with sodium iodide in acetone and silver nitrate in ethanol, why should 2-bromobutane react faster than 2-chlorobutane? Standards Reference tests done in Classification Tests for Halides Lab. Sodium Iodide in Acetone Test. Why E1 will occur in silver nitrate in ethanol reaction? Sodiumiodide and potassium iodide are soluble in acetone, but the corresponding bromidesand chlorides are not soluble. Add 2 mL of a 15% solution of sodium iodide in acetone, noting the time of addition. If we take alkyl iodide in place of alkyl chloride or alkyl bromide and metal chloride or metal bromide in place of metal iodide then reaction will not take place, due to following reason – Acetone is a polar aprotic solvent which is a covalent compound so it can dissolve covalent compounds in it. Iodide is an excellent nucleophile, and acetone is a nonpolar solvent. This white... See full answer below. Upon mixing, the precipitate of sodium iodide should dissolve. If you dissolve some potassium iodide, KI, in water, you will find that the outside of the container feels cold to the touch. Likewise the air is a solution of gas solutes in a gas solvent. And it just so happens that the acetone molecule can mix with MOST organic solvents…i.e. Thanks Because sodium iodide is much more soluble than sodium chloride in acetone, when you do this you see a glassy precipitate of sodium chloride in the acetone. But if you dissolve some sodium hydroxide, NaOH, in the same way, the outside of the container feels hot. Why E2 will not occur in the sodium iodide in acetone reaction? Procedure In a test tube place 0.25 mL or 0.2 g of your unknown. 1) The formation of white precipitate in the reaction of the unknown with sodium iodide and acetone indicates the presence of alkyl halide. Explain this rate difference. I think there is a named organic spot test for this reaction (its name escapes me at the moment, I should not have finished that bottle of … Question: Reagent Is Sodium Iodide With Acetone Reagent Is Silver Nitrate In Ethanol 1-Bromobutane 1-Bromobutane 1-Chlorobutane 1-Chlorobutane 2-Bromobutane 2-Bromobutane 2-Chlorobutane 2-Chlorobutane 1-Chloro-2-methylpentane 1-Chloro-2-methylpentane List The Alkyl Halides In Table Above In Order Of Decreasing Reactivity Toward Each Of The Nucleophiles. Thetendency to form a precipitate increases the completeness of the reaction. Please Helppp!!!!!! 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